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Exam Code: 1Z0-047
Exam Name: Oracle (Oracle Database SQL Expert)

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NO.1 You need to load information about new customers from the NEW_CUST table into the tables CUST
and CUST_SPECIAL. If a new customer has a credit limit greater than 10,000, then the details have to be
inserted into CUST_SPECIAL. All new customer details have to be inserted into the CUST table. Which
technique should be used to load the data most efficiently?
A.external table
B.the MERGE command
C.the multitable INSERT command
D.INSERT using WITH CHECK OPTION
Answer:C

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NO.2 View the Exhibit and examine the structure of the EMP table which is not partitioned and not an
index-organized table. Evaluate the following SQL statement: ALTER TABLE emp DROP COLUMN
first_name; Which two statements are true regarding the above command? (Choose two.)
A.The FIRST_NAME column would be dropped provided it does not contain any data.
B.The FIRST_NAME column would be dropped provided at least one or more columns remain in the table.
C.The FIRST_NAME column can be rolled back provided the SET UNUSED option is added to the above
SQL statement.
D.The FIRST_NAME column can be dropped even if it is part of a composite PRIMARY KEY provided the
CASCADE option is used.
Answer:B D

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NO.3 Evaluate the CREATE TABLE statement: CREATE TABLE products (product_id NUMBER(6)
CONSTRAINT prod_id_pk PRIMARY KEY, product_name VARCHAR2(15)); Which statement is true
regarding the PROD_ID_PK constraint?
A.It would be created only if a unique index is manually created first.
B.It would be created and would use an automatically created unique index.
C.It would be created and would use an automatically created nonunique index.
D.It would be created and remains in a disabled state because no index is specified in the command.
Answer:B

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NO.4 View the Exhibit and examine the data in ORDERS and ORDER_ITEMS tables. You need to create a
view that displays the ORDER ID, ORDER_DATE, and the total number of items in each order. Which
CREATE VIEW statement would create the view successfully?
A.CREATE OR REPLACE VIEW ord_vu (order_id,order_date) AS SELECT o.order_id, o.order_date,
COUNT(i.line_item_id) "NO OF ITEMS" FROM orders o JOIN order_items i ON (o.order_id = i.order_id)
GROUP BY o.order_id,o.order_date;
B.CREATE OR REPLACE VIEW ord_vu AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)
"NO OF ITEMS" FROM orders o JOIN order_items i ON (o.order_id = i.order_id) GROUP BY
o.order_id,o.order_date;
C.CREATE OR REPLACE VIEW ord_vu AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)
FROM orders o JOIN order_items i ON (o.order_id = i.order_id) GROUP BY o.order_id,o.order_date;
D.CREATE OR REPLACE VIEW ord_vu AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)||'
NO OF ITEMS' FROM orders o JOIN order_items i ON (o.order_id = i.order_id) GROUP BY
o.order_id,o.order_date WITH CHECK OPTION;
Answer:B

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NO.5 View the Exhibit and examine the description of the CUSTOMERS table. You want to add a constraint
on the CUST_FIRST_NAME column of the CUSTOMERS table so that the value inserted in the column
does not have numbers. Which SQL statement would you use to accomplish the task?
A.ALTER TABLE CUSTOMERS ADD CONSTRAINT cust_f_name
CHECK(REGEXP_LIKE(cust_first_name,'